If 2k+1,6,3k+1 are in A. P. Then find the value of k.
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hello users....
we have given that
2k+1,6,3k+1 are in A. P.
we have to find k= ?
solution:-
we know that
if a,b,c are in AP
then
2b = a+c
here,
2×6 = { (2k+1) +(3k+1)}
=> 12= 5k+2
=> 5k = 10
=> k=2 answer
⭐⭐ hope it helps ⭐⭐
we have given that
2k+1,6,3k+1 are in A. P.
we have to find k= ?
solution:-
we know that
if a,b,c are in AP
then
2b = a+c
here,
2×6 = { (2k+1) +(3k+1)}
=> 12= 5k+2
=> 5k = 10
=> k=2 answer
⭐⭐ hope it helps ⭐⭐
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