Question

If 2k+1, 6, 3k+1 are in AP, then value of k is *

Answer 1

Answer:

Hence, the required value of k is 2.

Step-by-step explanation:

Here,

2k+1, 6 and 3k+1 are in AP.

Therefore, 6 - (2k+1) = 3k+1 - 6

or, 6 - 2k - 1 = 3k - 5

or, 3k + 2k = 6 - 1 + 5

or, 5k = 10

Therefore, k = 2.