Question

if 2k + 1,6,3k+1 are three consecutive terms of an ap then find k​

Answer 1

Answer:

now a=2k+1 , a+d= 6 and a+2d=3k+1

as you know that all of 3 terms which use to be in AP are of the form :

a+d, a, a-d

so..

Step-by-step explanation:

2k+1+d=6

2k+d=5

and, 2k+1 +2d=3k+1 k-2d=0

from here, we got 2 equations,

so, from solving this by elimination method, 5d=5 so, d=1 so,

2(k+1)=6

so, k=2

Answer 2

Answer:

great behen but this one could be solved by otger method too when you would assume 6=a which you were supposed to do earlier....but your way is also correct and acceptable