Question

If 2k, 3k-1, 8 are in A.P. Then the value of k is :​

Answer 1

if 2k ,3k-2,8 are in then

there common common difference d is same.

then ,. 3k-2-2k= 8-3k+2

k-2 = 10-3k

4k = 12

k = 3

I hope it helps you...

Answer 2

Answer:

IN A,B,C are in AP Then

A+C=2B

2k+8=2(3k-1)

2k+8=6k-2

8+2=4k

10/4=k

5/2=k