Question

. If 2k, 3k - 1,8 are in A.P., then what is the value of k?​

Answer 1

ANSWER :

They are in AP therefore we can use the formula,

2b = a + c

2(3k - 1) = 2k + 8

6k - 2 = 2k + 8

4k = 10

k = 10/4 = 5/2

OTHER METHOD

In an AP, common difference is same

Therefore, a2 - a1 = a3 - a2

3k - 1 - 2k = 8 - 3k + 1

k - 1 = 9 - 3k

4k = 10

k = 10/4 = 5/2

Hope it helps....

Answer 2

Step-by-step explanation:

answer is 5/2.Guys pls support me and like my answer