Question

IF 2K, 3K-1 and 8
are first 3 term of an Ap, find the value of k
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Answer 1

Answer:

$according \: \: to \: \: a.p. \: = > \\ \\ 2(3k - 1) = 2k + 8 \\ \\ 6k - 2 = 2k + 8 \\ \\ 4k = 10 \\ \\ k = \frac{5}{2}$