Question

If 2k+4, 3k-7 and k+12 are in A.P, then k =

Answer 1

Answer:

k=10

Step-by-step explanation:

3k-7 - (2k+4) = (k+12) - (3k-7)

k - 11 = -2k 19

3k = 30

k = 10

Answer 2

Given,

2k+4, 3k-7 and k+12 are in an A.P

To find,

The value of k

Solution,

The value of k is 10.

We can simply solve the mathematical problem by the following procedure.

We know by sequence and series that in an A.P, the difference between the successive terms is equal to a number known as the common difference of the A.P or Arithmetic Progression.

With the help of this knowledge, we can say that, if 2k+4, 3k-7, and k+12 are in A.P, the common difference will be constant.

Thus,

⇒ (3k - 7) - (2k + 4) = (k + 12) - (3k - 7)

⇒ 3k - 7 - 2k - 4 = k + 12 - 3k + 7

⇒ k - 11 = -2k + 19

⇒ 3k = 30

∴ k = 10

As a result, by simplifying the equation, we get the value of k to be 10.