If 2k, k + 10, 3k + 2 are in AP, the value of k is ....
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1
Answer:
6
Step-by-step explanation
Since it is an A.P,the common differences will be same .....
Therefore t2-t1=t3-t2
K+10-2k=3k+2-k-10
-k+10=2k-8
-3k=-8-10
K=18÷3=6
HOPE IT HELPS....
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