Question

if 2k, k + 10 and 3k + 2 are three consecutive terms of an A.P., then find the value of k​

Answer 1

Answer:

As 2k, k + 10 and 3 k + 2 are the three consecutive terms of an AP so k + 10 will be the one arithmetic mean between 2k and

3k + 2

which means that twice of a + 10 will be equals to sum of other two terms i.e.

$2(k + 10) = 2k + 3k + 2 \\ \implies \: 2k + 20 = 5k + 2 \\ \implies \: 20 - 2 = 3k \\ \implies \: k = \frac{18}{3} = 6 \: \: \: \: \: \: \: \: \boxed{ \boxed{Answer}}$

so for k = 6

given three terms will be three consecutive terms of an AP.

Answer 2

Answer:

Step-by-step explanation:

Hope it helps you.....