Math, asked by kumarpranjal955, 6 months ago

if (2ka power 3x-1+10)÷7=6,then the value of x is​

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Answered by rayyanuddin027
1

Answer:

Step-by-step explanation:

If (2^3x-1 +10) ÷7=6 then find the value of x?

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(2^3x-1 +10)÷7=6

(2^3x-1 +10)/7=6

(2^3x-1 +10)=42

2^3x-1=42–10=32

(2)^3x-1=(2)^5

3x-1=5

3x=6

x=6/3

x=2 ,

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