Question

If 2log 3 +1/3log8_log2=logx
then find the value of x​

Answer 1

Answer:

I am not a mathematician but I found this to be Very interesting.

*If:*

*A = 1 ; B = 2 ; C = 3 ; D = 4 ;*

*E = 5 ; F = 6 ; G = 7 ; H = 8 ;*

*I = 9 ; J = 10 ; K = 11 ; L = 12 ;*

*M = 13 ; N = 14 ; O = 15 ; P = 16 ;*

*Q = 17 ; R = 18 ; S = 19 ; T = 20 ;*

*U = 21 ; V = 22 ; W = 23 ; X =24 ;*

*Y = 25 ; Z = 26.*

*Then,*

*H+A+R+D+W+O+R+K*

=8+1+18+4+23+15+18+11

*= 98%*

*K+N+O+W+L+E+D+G+E*

=11+14+15+23+12+5+4+7+5

*=96%*

*L+O+V+E*

= 12+15+22+5

*= 54%*

*L+U+C+K ;*

=12+21+3+11

*= 47%*

*None of them makes 100%.*

*Then what makes 100%?*

*Is it Money?*

.

*NO!*

*M+O+N+E+Y*

= 13+15+14+5+25

*=72%*

*Leadership?*

.

*NO!*

*L+E+A+D+E+R+S+H+I+P*

=12+5+1+4+5+18+19+8+9+16

*=97%*

*Every problem has a solution, only if we perhaps change our*

*"ATTITUDE"...*

*A+T+T+I+T+U+D+E ;*

1+20+20+9+20+21+4+5

*= 100%*

*It is therefore OUR ATTITUDE towards Life* *and Work that makes*

*OUR Life 100% Successful.*

*Amazing mathematics

*plz share it to all ur friends*

Answer 2

Step-by-step explanation:

Explanation:

Use the property of condensation of logarithmic function

Given,

#log (x-2)-log (2x-3)=log (2)#

# or, log ((x-2)/(2x-3)) = log (2)#

# or, 10^(log ((x-2)/(2x-3))=10^(log (2))#

# or, (x-2)/(2x-3)=2#

# or, (x-2)=2 (2x-3)#

# or, (x-2)=4x-6#

# or, -2+6=4x-x#

# or, 4=3x#

#:.x=4/3#

like that u have to do