Question

If 2log416 + log432 - Blog/162 = x, then solve for X​

Answer 1

Step-by-step explanation:

If 2log416 + log432 - Blog/162 = x, then solve for X=1/2

Answer 2

Answer:

We can find the value of $x$ to apply the logarithm formula in the given question. Answer: The value of $x=1.245$

Step-by-step explanation:

Question: $2\log416+\log 432-3\log162=x$

To find the value of $x$,

Step 1: Logarithm Formula: $n\log_{a} x=\log_{a} x ^n$.Apply this formula in the above question. That is,

              $2\log416=\log 416^2$

              $3\log162=\log 162^3$

$\log416^2+\log 432-\log162^3=x$   ----------------(1)

Step 2: Logarithm Formula: $\log_{a} x+\log_{a}y=\log_{a} (xy)$.Apply this formula in equation(1). That is,

               $\log416^2+\log 432= \log(416^2*432)$

  $\log(416^2*432)-\log162^3=x$   ----------------(2)

Step 3: Logarithm Formula: $\log_{a} x-\log_{a}y=\log_{a} \frac{x}{y}$.Now apply this formula in equation(2). That is,

  $\log(416^2*432)-\log162^3=\log\frac{416^2*432}{162^3}$

                        $\log\frac{416^2*432}{162^3}=x$

                    $\log\frac{416*416*432}{162*162*162}=x$

Step 4: Simplify the equation in th step 3 we cant get the following value. That is,

                         $\log17.584=x$

Step 5: Using logarithm table in log book the value of $\log17.584$ is,

                         $\log17.584=1.245$

Step 6: The value of $x=1.245$