if 2logb-loga-logc=0 then express b in terms of a and c
Answers
Answered by
2
Step-by-step explanation:
=> 2logb = loga + logc
=> logb² = log(ac)
=> b² = ac
=> b = √(ac)
Answered by
0
I tried to simplify this by different methods like using the identity logba=1logab, but I couldn't get anywhere. Addition, subraction can't be used. I am not able to figure out a way to simplify the LHS. It would be great if someone could help me to proceed with this problem.
Similar questions