Math, asked by siddivinay, 1 month ago

If 2m-1/ 2m=2,, where (m≠0) then the value of m²+ 1/16m² is

Answers

Answered by Anonymous
2

Answer:

Correct option is

B

2

 

2m−  

2m

1

=2

dividing by 2

m−  

4m

1

=1

square both sides,

(m−  

4m

1

)  

2

 

⇒m  

2

+  

16m

1

−  

2

1

=1

⇒m  

2

+  

16m  

2

 

1

=1+  

2

1

=  

2

3

 

=  

2

3

 

Then (m+  

4m

1

)  

2

=m  

2

+  

16m  

2

 

1

+2×m×  

4

1

⇒(m+  

4m

1

)  

2

=  

2

3

+  

2

1

=2

Then m+  

4m

1

=  

2

 

m  

2

−  

16m  

2

 

1

=(m+  

4m

1

)(m−  

4m

1

)=  

2

×1=  

2

Correct option is

B

2

 

2m−  

2m

1

=2

dividing by 2

m−  

4m

1

=1

square both sides,

(m−  

4m

1

)  

2

 

⇒m  

2

+  

16m

1

−  

2

1

=1

⇒m  

2

+  

16m  

2

 

1

=1+  

2

1

=  

2

3

 

=  

2

3

 

Then (m+  

4m

1

)  

2

=m  

2

+  

16m  

2

 

1

+2×m×  

4

1

⇒(m+  

4m

1

)  

2

=  

2

3

+  

2

1

=2

Then m+  

4m

1

=  

2

 

m  

2

−  

16m  

2

 

1

=(m+  

4m

1

)(m−  

4m

1

)=  

2

×1=  

2

Step-by-step explanation:

Answered by vakanksha511
0

Answer:

here is the required answer

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