if 2ma of current is flowing through a 4 ohm what is voltage across drop the resistor
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sheujejVjevejjgjejjec
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hey mate .....
your answer is here....
current(I) = 2ma
resistance (r) = 4 ohm
voltage(v) =current × resistance
v = ir
v = 2ma × 4 ohm
v = 2 × 10 ^-3 volt
I hope it helps...✌✌✌✌
thanks; D
your answer is here....
current(I) = 2ma
resistance (r) = 4 ohm
voltage(v) =current × resistance
v = ir
v = 2ma × 4 ohm
v = 2 × 10 ^-3 volt
I hope it helps...✌✌✌✌
thanks; D
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