Question

if 2mn sin theta= (m²-n²) cos theta, then an incorrect statement is A. sec theta= m²+n²/2mn B.tan theta=m²+n²/m²-n² C. cosec theta=m²-n²/m²+n² D. sin theta= m²-n²/m²+n²​

Answer 1

Answer:

A is wrong

Step-by-step explanation:

In the attachment

Answer 2

Answer:

A andD are wrong

Step-by-step explanation:

2mnsinθ=(m2−n2)cosθ

tanθ=(m2−n2)2mn

BC2=AB2+AC2

BC2=(m2−n2)2+(2mn)2=(m2−n2)2+4m2n2=(m2+n2)2

secθ=(m2+n2)2mn  

sinθ=(m2−n2)(m2+n2)

PLEASE MARK AS BRAINLIEST