If 2n = 4096, then 2n – 5
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Given , <br> `2^n=4096=2^12` <br> <br> `therefore 2^(n-5)=(2^n)/(2^5)=(2^12)/(2^5)=2^(12-5)=2^7=128` <br> Hence, the correct option is (a).
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