Question

if 2n-5, 2n-8. 2n-11 are in A. P. then (p+ 2)"term is
a) 2n - 3p-8 b) 2n-3p+8 c) 2n + 3p-8
d) 2n + 3p+8​
please send answer

Answer 1

Answer:

is this a real question or you made it randomly

Step-by-step explanation:

Answer 2

Answer:

2n - 3p - 8

Step-by-step explanation:

a = 2n – 5, d = (2n – 8) – (2n – 5) = – 3

$t_{p+2} = a + (p + 2 - 1)d \\t_{p+2} = a + (p + 1)d \\t_{p+2} = 2n - 5 - 3 (p + 1)\\t_{p+2}= 2n - 5 - 3p - 3\\t_{p+2} = 2n - 3p - 8$

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