Question

if (2n+5)=3(3n-10) then n ?​

Answer 1

$\begin{cases}\large\bf{\purple{ \longrightarrow}} \tt \: (2n + 5) \: = \: 3(3n - 10) \\ \\ \large\bf{\purple{ \longrightarrow}} \tt \: 2n \: + \: 5 \: = \: 9n \: - \: 30 \\ \\ \large\bf{\purple{ \longrightarrow}} \tt \: 30 \: + \: 5 \: = \: 9n \: - \: 2n \\ \\ \large\bf{\purple{ \longrightarrow}} \tt \: 35 \: = \: 7n \\ \\ \large\bf{\purple{ \longrightarrow}} \tt \: n \: = \: \cancel\frac{35}{7} \\ \\ \large\bf{\purple{ \longrightarrow}} \tt \: n \: = \: 5 \end{cases}$

Answer 2

$\begin{gathered} \begin{cases}\large\bf{\pink{ \longrightarrow}} \tt \: (2n + 5) \: = \: 3(3n - 10) \\ \\ \large\bf{\pink{ \longrightarrow}} \tt \: 2n \: + \: 5 \: = \: 9n \: - \: 30 \\ \\ \large\bf{\pink{ \longrightarrow}} \tt \: 30 \: + \: 5 \: = \: 9n \: - \: 2n \\ \\ \large\bf{\pink{ \longrightarrow}} \tt \: 35 \: = \: 7n \\ \\ \large\bf{\pink{ \longrightarrow}} \tt \: n \: = \: \cancel\frac{35}{7} \\ \\ \large\bf{\pink{ \longrightarrow}} \tt \: n \: = \: 5 \end{cases}\end{gathered}$