Question

If (2n+5)^5=a5n^5+a4n^4+a3n3+a2n^2+a1n+a0 is an inequation then prove a0-2a1+4a2-8a3+16a4-32a5=?​

Answer 1

Answer:

As a

1

,a

2

,a

3

,a

4

,a

5

are in A.P., we have a

1

+a

5

=a

2

+a

4

=2a

3

.

Hence ∑

i=1

5

=10.