Question

If 2n,n+10,3n+2 are in AP , find the value of n​

Answer 1

Answer: if theuy are in ap, difference= d(let)

3n+2-n-10=d =n+10-2n

=> 2n-8=10-n

=>3n=18

n=6

Step-by-step explanation:

Answer 2

Answer:

$\blue{n=2/-3}$

Step-by-step explanation:

$\boxed{given}$

2n,n+10,3n+2

are in Ap

$\boxed{Tofind}$

value of x

$\boxed{Answer}$

we can find it by using common diffrence

we know that the terms in an Ap has same common difference

so ,consider

$a2 = n + 10$

$a1 = 2n$

$a3 = 3n + 2$

Then

$a2 - a1 = a3 - a2$

$n + 10 - 2n = 3n + 2 - n + 10$

$- n + 10 = 2n + 12$

$- n - 2n = 12 - 10$

$- 3n = 2$

$n = \frac{2}{ - 3}$