if (2p+1),13,(5p-3) are in AP,find value of p.
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Since they are in AP
The common difference is constant
T3 - T2 = T2 - T1
=> 5p-3-13 = 13 - 2p - 1
=> 5p - 16 = 12 - 2p
=> 7p = 28
=> p= 4
p = 4
The common difference is constant
T3 - T2 = T2 - T1
=> 5p-3-13 = 13 - 2p - 1
=> 5p - 16 = 12 - 2p
=> 7p = 28
=> p= 4
p = 4
Kajalkumari9599:
right
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0
i hope u get answer
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plz marks as a brainlist
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oh sorry this answer is 4
ya its ans is 4
you have solved wrong
i know
okk
even thnks for it
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