Question

if 2p-1/2p=3, prove that 64p^6-48p^4-216p^3+12p^2=1

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Given:

(2p) - (1/2p) = 3

((2p)^2 - 1) / 2p = 3

((2p)^2 - 1) = 6p

Cubing on both sides,

((2p)^2 - 1)^3 = (6p)^3

Using (a - b)^3 = a^3 - 3*a^2*b + 3*a*b^2 - b^3

((2p)^2)^3 - 3* ((2p)^2)^2 * 1 + 3*(2p)^2) * 1 - 1= 216p^3

64p^6 - 48p^4 + 12p^2 - 1 = 216p^3

64p^6 - 48p^4 + 12p^2 - 216p^3 = 1

64p^6 - 48p^4 - 216p^3 + 12p^2 = 1

Hence Proved