Question

if 2p-1 , 3p+1 , 11 are AP find the value of P its very important anybody can help

Answer 1

since 2p-1, 3p+1 and 11 are in A.P, then

2×middle term =first term + third term,

2×(3p+1)=2p-1 + 11,

6p+2=2p+10,

6p-2p=10-2,

4p=8,

then

p=8/4,

p=2

Answer 2

t2-t1 =t3-t2
3p+1 -(2p-1) =11-(3p+1)
3p+1 -2p+1 =11-3p-1
p+2=-3p+10
p+3p=10-2
4p=8
p=8/4
p=2 is answer obtained