Math, asked by xivafof791, 7 months ago

If (2p+1 , P/2) is a solution of equation
x-ry=5 then find the value of p .

Answers

Answered by sksonawane34
1

Answer:

p= 8 / 4 - r

Step-by-step explanation:

( 2p+1 , p/2) is the soln

2p+1 = x p/2 = y

Substitute x & y in eqn

2p+1 - r(p/2)

4p + 2 - rp = 10

4p - rp = 8

p = 8/ 4-r

Answered by eshnehatamang385
0

Answer:

p ≠ 4

Step-by-step explanation:

The Given pair of  linear equation is :

(p+ 2)x - (2p + 1)y  =  3(2p -1) ……….(1)

2x-  3y  = 7 ………….(2)

On comparing with General form of a pair of linear equations  in two variables x & y is:

a1x + b1y + c1 = 0

and   a2x + b2y + c2= 0

a1= (p+2) , b1= - (2p+1), c= - (3(2p -1))

a2= 2 , b2= -3 , c= -7

a1/a2= (p+2) /2 ,  b1/b2=  -(2p+1)/-3

Given: A pair of linear equations has a Unique solution, if

a1/a2 ≠ b1/b2

(p+2) /2 ≠ -(2p+1)/-3

-3(p+2) ≠ 2(-2p-1)

-3p -6 ≠ -4p -2

-3p + 4p ≠ - 2 +6

p ≠ 4

Hence, the value of p ≠ 4

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