If (2p+1 , P/2) is a solution of equation
x-ry=5 then find the value of p .
Answers
Answered by
1
Answer:
p= 8 / 4 - r
Step-by-step explanation:
( 2p+1 , p/2) is the soln
2p+1 = x p/2 = y
Substitute x & y in eqn
2p+1 - r(p/2)
4p + 2 - rp = 10
4p - rp = 8
p = 8/ 4-r
Answered by
0
Answer:
p ≠ 4
Step-by-step explanation:
The Given pair of linear equation is :
(p+ 2)x - (2p + 1)y = 3(2p -1) ……….(1)
2x- 3y = 7 ………….(2)
On comparing with General form of a pair of linear equations in two variables x & y is:
a1x + b1y + c1 = 0
and a2x + b2y + c2= 0
a1= (p+2) , b1= - (2p+1), c= - (3(2p -1))
a2= 2 , b2= -3 , c= -7
a1/a2= (p+2) /2 , b1/b2= -(2p+1)/-3
Given: A pair of linear equations has a Unique solution, if
a1/a2 ≠ b1/b2
(p+2) /2 ≠ -(2p+1)/-3
-3(p+2) ≠ 2(-2p-1)
-3p -6 ≠ -4p -2
-3p + 4p ≠ - 2 +6
p ≠ 4
Hence, the value of p ≠ 4
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