Question

if 2p -4 = 2 and 0.01 q = 0.1, then the value of 3p^2 - q^2

Answer 1

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Answer 2

$\large\bf{ \underline{Given:- }}$

• $\sf{2p - 4 = 2}$
• $\sf{0.01q = 0.1}$

$\large \bf {\underline{To \: Find :-}}$

• $\sf {3 {p}^{2} - {q}^{2} }$

$\large\bf{\underline{Solution :-}}$

$\star \sf{ \: 2p - 4 = 2 }$

$⇒ \sf{ 2p = 6}$

$⇒ \sf{p = 3}$

$\star \sf{ \: 0.01q = 0.1}$

$⇒ \sf{q = \frac{0.1}{0.01} }$

$⇒ \sf{q = 10}$

now,

$✺ \sf{ \: 3 {p}^{2} - {q}^{2} }$

$↝ \sf{3 \times {(3)}^{2} - {(10)}^{2} }$

$↝\sf{3 \times 9 - 100}$

$↝27 - 100$

$↝\sf{ - 73}$

$\bigstar \sf{ \: Hence, \: value \: of \: \sf{ \: 3 {p}^{2} - {q}^{2} }\:is \: - 73 }.$