Question

If 2r = h + V2 +h2, the value of r: his (r, h0)
(B) 1:2
(D) 2:1
(A)3:4
(c) 4:3
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Answer 1

Answer:

The required ratio would be ¾.

Step-by-step explanation:

Correct Question: 2r = h + √r²+h²

2r = h + √r²+h²

2r = h + h√(r²/h²+1)

2r - h = h√(r²/h²+1)

(2r-h)/h = √(r²/h²+1)

2r/h - h/h = √(r²/h²+1)

2r/h - 1 = √(r²/h²+1)

Squaring both sides:

[2r/h - 1]²= [√(r²/h²+1)]²

4r²/h2 + 1 - 2.2r/h.1 = r²/h² + 1

4r²/h² + 1 - 4r/h = r²/h² + 1

4r²/h²- 4r/h = 1 - 1 + r²/h²

4r²/h²- 4r/h = r²/h²

4r/h(r/h - 1) = r²/h²

r/h - 1 = r²/h² × h/4r

r/h - 1 = r/4h

r/h - r/4h = 1

(4r-r)/4h = 1

4r - r = 1 * 4h

3r = 4h

r/h = 3/4

Therefore, the required ratio would be ¾.

Answer 2

Answer:

If 2r=h+√ (r^2+h^2) where r is not equal to 0, what is r:h?

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2r=h+√(r^2+h^2)

or. 2r-h=√(r^2+h^2)

Squaring both sides.

4r^2–4r.h+h^2=r^2+h^2

or. 3r^2=4r.h

Dividing both side by r.h

or. 3r/h=4

or. r/h= 4/3

or. r : h = 4 : 3. Answer