Question

If 2raise to 12+2raise to 12 =2r
aise to n, then find the value of n?
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Answer 1

Answer:

n = 13

Step-by-step explanation:

${2}^{12} + {2}^{12} = {2}^{n} \\ 2 \times {2}^{12} = {2}^{n} \\ {2}^{1} \times {2}^{12} = {2}^{n} \: \: \: \: {a}^{1} = a \\ {2}^{1 + 12} = {2}^{n} \: \: \: \: \: \: \: \: \: {a}^{m} \times {a}^{n} = {a}^{m + n} \\ {2}^{13} = {2}^{n} \: \: \: \: \: \: \: \: \: \: \: \: \: when \: bases \: are \: equal their \: exponents \: also \: become \: equa \\ n = 13$