if 2root=1.414 value of 3/32root-2/50root+4/128root-20/18root
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Hi ,
It is given that ,
√2 = 1.414---( 1 )
√32 = √(4×4×2) = 4√2
√50 = √(5 × 5 × 2 ) = 5√2
√128 = √ ( 8×8×2 ) = 8√2
√18 = √ ( 3×3×2 ) = 3√2
Now ,
3/√32 - 2/√50 + 4/√128 - 20/√18
= 3/4√2 - 2/5√2 + 4/8√2 - 20/3√2
= 1/√2 [ 3/4 -2/5 + 4/8-20/3 ]
= 1/√2 [ 3/4 -2/5 + 1/2 - 20/3]
= (√2/√2×√2)[ (45-24+60-400)/60]
=√2/120 [ -319 ]
= ( 1.414 /120)( - 319 )
≈ - 3.75
I hope this helps you.
: )
It is given that ,
√2 = 1.414---( 1 )
√32 = √(4×4×2) = 4√2
√50 = √(5 × 5 × 2 ) = 5√2
√128 = √ ( 8×8×2 ) = 8√2
√18 = √ ( 3×3×2 ) = 3√2
Now ,
3/√32 - 2/√50 + 4/√128 - 20/√18
= 3/4√2 - 2/5√2 + 4/8√2 - 20/3√2
= 1/√2 [ 3/4 -2/5 + 4/8-20/3 ]
= 1/√2 [ 3/4 -2/5 + 1/2 - 20/3]
= (√2/√2×√2)[ (45-24+60-400)/60]
=√2/120 [ -319 ]
= ( 1.414 /120)( - 319 )
≈ - 3.75
I hope this helps you.
: )
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