Math, asked by tejudeepthi02, 3 months ago

if 2root 3 - root 5 /4 root 3 - 3 root 5 =x - root 15y, find the value of x and y​

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Answered by Rishita24680
0

Answer:

 \frac{2 \sqrt{3} -  \sqrt{5}  }{4 \sqrt{3} - 3 \sqrt{5}  }  \times  \frac{4 \sqrt{3} + 3 \sqrt{5}  }{4 \sqrt{3}  + 3 \sqrt{5}  }  \\  \frac{(2 \sqrt{3} - 3 \sqrt{5})(4 \sqrt{3}    + 3 \sqrt{5})}{ {(4 \sqrt{3}) }^{2}  -  {(3 \sqrt{5} }^{2}) } \\  \frac{(2 \sqrt{3} - 3 \sqrt{5})(4 \sqrt{3}    + 3 \sqrt{5})}{48 - 45} \\  \frac{ (2 \sqrt{3} - 3 \sqrt{5})(4 \sqrt{3}    + 3 \sqrt{5} )}{3} \\  \frac{8(3) + 6( \sqrt{15} ) - 12( \sqrt{15} ) - 9(5)}{3}  \\  \frac{24 - 6 \sqrt{15}  -45 }{3}

 -  \frac{(6 \sqrt{15}  + 21) }{3}  \\  -  \frac{3(2 \sqrt{15}  + 7)}{3}  \\  - (2 \sqrt{15}  + 7) \\  - 7 - 2 \sqrt{15}

Step-by-step explanation:

so

x= -7

y=2

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