Question

if 2root6+root5/3root5+2root6+p+root30q find p and q

Answer 1

Hey mate!!

$\bold{ \frac{2 \sqrt{6} + \sqrt{5} }{3 \sqrt{5} + 2 \sqrt{6} } = p + \sqrt{30} q} \\ \\ \frac{2 \sqrt{6} + \sqrt{5} }{3 \sqrt{5} + 2 \sqrt{6} } \times \frac{3 \sqrt{5} - 2 \sqrt{6} }{3\sqrt{5} - 2 \sqrt{6}} \\ \\ \frac{6 \sqrt{30} - 24 + 15 - 2 \sqrt{30} }{(3 \sqrt{5}) {}^{2} - (2 \sqrt{6} ) {}^{2} } \\ \\ \frac{4 \sqrt{30} - 9 }{45 - 24} \\ \\ \frac{4 \sqrt{30} - 9}{21}$
.Hence, you can conclud the values.


Thanks for the question!!