Question

If 2sin^2(π/4+A)=l+ msin2A then find l&m​

Answer 1

Answer:

$\: \: \: \: \: 2 \sin {}^{2} ( \frac{\pi}{4} + x ) \\ = 1 - \cos(2(\frac{\pi}{4} + x)) \\ = 1 - \cos(\frac{\pi}{2} + 2 x) \\ = 1 + \sin(2x)$

Compare I = 1 and m = 1

Answer 2

Answer:

Step-by-step explanation:

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