Question

if 2sin^2 - cos^2 = 2 then find the value of theta

Answer 1

2sin^2--cos^2=2(cos^2+sin^2)
2sin^2-cos^2=2sin^2+2cos^2
-cos^2=2cos^2
2cos^2+cos=0
3cos^2=0
cos^2=0
cos^2∅=cos^290
∅=90

Answer 2

I hope that's helpful for you