Question

if 2sin^2 teta-cols^2 teta equal to 2 then find the value of teta​

Answer 1

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From the question,

2 sin²Θ - cos²Θ = 2

2 sin²Θ - 2 =  cos²Θ

From the Identity ⇒ sin²Θ + cos²Θ = 1

2(sin²Θ - 1) = cos²Θ

  2(- cos²Θ) = cos²Θ

    - 2 cos²Θ = cos²Θ

      3 cos²Θ = 0

         cos²Θ = 0

From the Trigonometric table cos 90° = 0 ⇒ cos² 90° = 0

Then, cos²Θ = cos² 90°

Cancelling cos²Θ on both sides,

         Θ = 90°

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