If 2sin^2 theta - cos^2 theta = 2 , then find the value of theta.
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Answered by
13
2sin^2theta -1+sin^2theta=2
3sin^2theta=3
sin^2theta=1
sintheta=√1=1
theta=90°
is your answer
3sin^2theta=3
sin^2theta=1
sintheta=√1=1
theta=90°
is your answer
Answered by
1
let theta =x
we get 2sin²x-cos²x=2
=>-cos²x=2-2sin²x
=>-cos²x=2(1-sin²x)
=>-cos²x=2cos²x
=>3cos²x=0
=>cos²x=0
=>x=2nπ±π/2
we get 2sin²x-cos²x=2
=>-cos²x=2-2sin²x
=>-cos²x=2(1-sin²x)
=>-cos²x=2cos²x
=>3cos²x=0
=>cos²x=0
=>x=2nπ±π/2
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