If 2sin^2 thita - cos thita =2 then thita =
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Explanation:
in place of thita i am using a since the symbol for thita cannot be typed.
2sin²A - cosA = 2
2(-cos²A+1) - cosA = 2
-2cos²A +2 -cosA =2
-2cos²A -cosA =0
cosA × (2cosA- 1)= 0
cosA = 0 ; 2cosA-1 = 0
cosA = cos90 ; cosA = 1/2
cosA = cos 90 ; cosA = 60
A= 90 or 60
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