if 2sin(2A+B)=1 and tan(A-B)=√3 find A and B
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see dear,
2sin(2A+B)=1 OR, sin(2A+B)=1/2 OR, using angles, 2A+B=30° ---- 1
and,
tan(A-B)=√3 OR, using angles, A-B=60° -----2
adding 1 and 2,
3A=90 or, A=30° now putting A=30 in eqn.1 we get B= -30
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