Question

If 2sin^2theta-cos^2theta=2. Find the value of theta

Answer 1

Answer:

Given:

2sin^2θ - cos^2θ = 2

2sin^2θ = cos^2θ + 2

2sin^2θ = 1 - sin^2θ + 2

(Since sin^2θ + cos^2θ = 1)

2sin^2θ + sin^2θ = 3

3sin^2θ = 3

sin^2θ = 1

sinθ = √1

sinθ = 1

sinθ = sin 90°

θ = 90°

Answer:

The value of θ is ${\huge{\boxed{\boxed{\mathbb{\purple{90°}}}}}}$

Hope this helps you.