Question

If 2sin(2x-15)=√3, then find the value of
sin^2(2x+10) tan^2(X+5)

Answer 1

Answer:

your answer is in the attachment

Answer 2

Given

$2 \sin(2x - 15) = \sqrt{3} \\ \sin(2x - 15) = \frac{ \sqrt{3} }{2} \\ \sin(2x - 15) = \sin(60) \\ 2x - 15 = 60 \\ 2x = 75 \\x = \frac{75}{2}$

Now

$= { (\sin((2x + 10) )}^{2} {( \tan2(x + 5)) }^{2} \\ = { \sin(2 \times \frac{75}{2} + 10) }^{2} { \tan(2( \frac{75}{2} + 5 )) }^{2} \\ = { \sin(85) }^{2} { \tan(85) }^{2}$

Hope it helped.....

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