Question

If 2sin (3x-15)=root3,then find the value of sin^2 (2x+10)°+tan^2 (x+5)°.

Answer 1

sin(3x-15)=√3/2

so 3x-15=60

x=25

sin^2(2*25+10)+tan^2(25+5)

sin^2(60)+tan^2(30)

3/4+1/3

13/12