Question

if 2sin a + 3cos a = 2 , then 3sin a -2cos a =​

Answer 1

Answer:

Given, 3cos 2 θ−3 sinθcosθ−3sin 2 θ=0⇒3cos2θ− 3 sin2θ=0⇒3 cos2θ−sin2θ=0⇒2 3 cos2θ− 2 1 sin2θ=0

⇒sin( 3π −2θ)=0⇒3π−2θ=nπ⇒2θ=nπ−3π