Question

if 2sin(a+b)≈√3 and tanb ≈1, find sin2b​

Answer 1

Answer:

2sin(a+b)=√3

sin(a+b)=√3/2=sin60

a+b=60

tan b=1=tan45

b=45

then sin 2b

=2sin b cos b

=2sin45.cos45

=2.1/√2.1/√2

=1