If 2sin(A+B)=sinA+sinB prove that tan(A/2)tan(B/2)=1/3
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Step-by-step explanation:
2sin(A)cos(B)+2sin(B)cos(A)=sin(A)+sin(B)
cos(B)=.5; cos(A)=.5
A and B are both either pi/3 or -pi/3
Tan(pi/6)Tan(pi/6)=1/3
tan(pi/6)^2=1/3
Tan(pi/6)=1/
Proven
Answered by
3
Step-by-step explanation:
1.extend sinA+sinB
2. extend sin(A+B)
THEN here you go .
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