If 2sin theta =2-cos theta and 0°<theta<90°. Find sin theta
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Answer:
sin theta = 1 or 3/5
Step-by-step explanation:
2sin theta =2-cos theta
from identity sin²theta + cos²theta =1
therefore cos²theta =1-sin²theta
square root both sides we get cos theta =√1-cos² theta
therefore 2sin theta = 2 - √1-sin² theta
√1-sin² theta=2-2sin theta
square both sides we get
1-sin² theta = (2-2sin theta)²
1-sin² theta = 4 - 8sin theta + 4sin² they
so 5sin² theta - 8 sin theta + 3 =0
5sin² theta - 3sin theta -5sin theta +3 =0
sin theta(5sin theta - 3) -1(5sin theta -3) =0
(sin theta - 1)(5sin theta - 3)=0
sin theta -1=0 or 5sin theta - 3=0
so sin theta = 1 or sin theta = 3/5
I hope this helps
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