Question

if 2sin theta - √3=0, then the value of 3 sin theta -4 sin ^3 theta is​

Answer 1

Answer:

6 because 3+3 is 6abd 2+2 is 4 that's why this answer

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let @ represents theta for the convenience of typing

Now,

2Sin@ - √3=0

Sin@=√3/2. ----- eq 1

As we know Sin 60 is √3/2

therefore; @=60

that means theta=@=60degrees

Now,

3 Sin@ - 4Sin³@ = 3Sin60-4Sin³60. ----- eq 2

From eq 1

Sin60 = √3/2

Put this in eq 2

3(√3/2) - 4(√3/2)³

= (3√3/2) - 4(3√3/8)

taking 3√3/2 common from both

= 3√3/2(1-(4/4))

=3√3/2(1-1)

=(3√3/2)(0)

=0

Therefore answer is 0.

Hope it will help you!