if 2sin theta = √3, (0° < theta <90° ), then find the value of theta
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2 sin theta= root3
Sin theta= root3/2 ———(1)
We know that,
Sin 60• = root3/2 ———(2)
On equating equation (1) and (2). We get;
Sin 60• = sin theta
60• = theta
So, theta is equal to 60 degree.
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2sinθ = √3
sinθ = √3/2
but, sin60 = √3/2
therefore θ = 60
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Plzz mark it brainliest
sinθ = √3/2
but, sin60 = √3/2
therefore θ = 60
----------------------------
Plzz mark it brainliest
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