If 2sin²∅ + 5 cos∅ = 4 ,. then prove that cos∅ = 1/2 ?
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I am writing it as A.
= > 2sin^2A + 5cosA = 4
= > 2(1 - cos^2A) + 5cosA = 4
= > 2 - 2cos^2A + 5cosA = 4
= > 2cos^2A - 5cosA + 2 = 0
= > (2cosA - 1)(cosA - 2) = 0
= > 2cosA - 1 = 0
cosA = 1/2.
Hope this helps!
= > 2sin^2A + 5cosA = 4
= > 2(1 - cos^2A) + 5cosA = 4
= > 2 - 2cos^2A + 5cosA = 4
= > 2cos^2A - 5cosA + 2 = 0
= > (2cosA - 1)(cosA - 2) = 0
= > 2cosA - 1 = 0
cosA = 1/2.
Hope this helps!
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