Question

If 2sin²θ-cos²θ=2 ,find the value ofθ​

Answer 1

Answer:

$2 {sin}^{2} \theta \: - \ { cos }^{2} \theta \: = \: 2$

$2 { \sin}^{2} \theta - (1 - { \sin }^{2} \theta) = 2$

$3 { \sin }^{2} \theta \: - 1 = 2$

${ \sin }^{2} \theta \: = 1$

Therefore,

$\sin( \theta) = 1$

so,

$\theta \: = \ \frac{\pi}{2}$