Question

If 2sin2B - cos2B = 2, then B is

Answer 1

Answer:

90 deg

2sin2β – cos2β = 2

Then 2 sin2β – (1- sin2β) = 2

3 sin2β =3 or sin2β =1

β is 90ᵒ

Answer 2

SOLUTION

CORRECT QUESTION

If 2sin²β – cos²β = 2 then β is

EVALUATION

Here it is given that

2sin²β – cos²β = 2

Now

2sin²β – cos²β = 2

⇒ 2sin²β – ( 1 - sin²β ) = 2

⇒ 2sin²β - 1 + sin²β = 2

⇒ 3sin²β - 1 = 2

⇒ 3sin²β = 3

⇒ sin²β = 1

⇒ sinβ = 1

⇒ β = 90°

FINAL ANSWER

If 2sin²β – cos²β = 2 then β is 90°

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