if 2sin2Q-cos2Q=2 find Q
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here Q=π/4 or can say 45°
because
2sin2(45°)-cos2(45°)=2
2sin(90°)-cos(90°)=2
2-0=2
2=2
LHS =RHS..
HENCE Q=π/4
because
2sin2(45°)-cos2(45°)=2
2sin(90°)-cos(90°)=2
2-0=2
2=2
LHS =RHS..
HENCE Q=π/4
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